Build a File This topic contains 5 replies, has 3 voices, and was last updated by 37mm 1 year ago. Author Posts February 5, 2016 at 7:48 am #34919 37mmParticipant I want to build a .txt file that has every file in a directory full path on each line. ls | select name | Out-File test.txt This is the contents test.txt Name ---- jns22.txt gps-position1.txt gps-position2.txt gps-position3.txt gps-position6.txt What I am looking for is the full path, and I don't want the column header (Name). Thanks in advance Fellas! February 5, 2016 at 8:13 am #34920 Wilfredo PerezParticipant Does it have to be a txt file. Can it be a csv file? February 5, 2016 at 8:24 am #34921 37mmParticipant No it doesn't have to a txt file. Now that I think of it, a csv would fix my issue! I don't think it will give me the full path of the file though. February 5, 2016 at 8:32 am #34922 Bob McCoyParticipant ls | select -ExpandProperty FullName | Out-File test.txt ls | select -Property FullName | Export-Csv test.csv February 5, 2016 at 8:36 am #34923 Wilfredo PerezParticipant You will need to use Fullname instead of name. Try something like this: (Get-ChildItem c:\ -Recurse).FullName | export-CSV c:\test.csv Also this one: Get-ChildItem c:\ -Recurse | out-file C:\Test\file.txt February 5, 2016 at 8:51 am #34924 37mmParticipant Thank you! Author Posts You must be logged in to reply to this topic.