- This topic has 5 replies, 3 voices, and was last updated 3 years, 10 months ago by
February 5, 2016 at 7:48 am #34919
I want to build a .txt file that has every file in a directory full path on each line.
ls | select name | Out-File test.txt
This is the contents test.txt
Name ---- jns22.txt gps-position1.txt gps-position2.txt gps-position3.txt gps-position6.txt
What I am looking for is the full path, and I don't want the column header (Name).
Thanks in advance Fellas!
February 5, 2016 at 8:13 am #34920ParticipantTopics: 16Replies: 108Points: 0Rank: Member
Does it have to be a txt file. Can it be a csv file?
February 5, 2016 at 8:24 am #34921
No it doesn't have to a txt file. Now that I think of it, a csv would fix my issue! I don't think it will give me the full path of the file though.
February 5, 2016 at 8:32 am #34922ParticipantTopics: 6Replies: 236Points: 0Rank: Member
ls | select -ExpandProperty FullName | Out-File test.txt ls | select -Property FullName | Export-Csv test.csv
February 5, 2016 at 8:36 am #34923ParticipantTopics: 16Replies: 108Points: 0Rank: Member
You will need to use Fullname instead of name. Try something like this:
(Get-ChildItem c:\ -Recurse).FullName | export-CSV c:\test.csv
Also this one:
Get-ChildItem c:\ -Recurse | out-file C:\Test\file.txt
February 5, 2016 at 8:51 am #34924
- The topic ‘Build a File’ is closed to new replies.