Capture second word in a line

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    by dragonfly26 at 2013-02-24 05:11:39

    I have an output file were i only need to capture the second word of each line.
    Removed windows6 on esx01
    I only need to caputre the word "windows6" in this example.

    by dragonfly26 at 2013-02-24 06:35:31

    I've solved it myself by using the following.

    ## Get content of txt file with multiple lines
    $lines = Get-Content c:\demo\lines.txt

    foreach ($_ in $lines){
    $out = $_.split()


    if someone can tell me how to do this with using regular expression, I am very intrested.

    by mjolinor at 2013-02-24 07:39:53

    One way:
    (Get-Content c:\demo\lines.txt -r 0) -replace '^\s*\S+\s(\S+)\s.+$','$1'

    by nohandle at 2013-02-24 12:35:05

    As I said on another forum I'd use -SPLIT " ",3 space as word separator and split only on first two occurances. But you could also use \b (word boundary) in similar manner.

    by mjolinor at 2013-02-24 13:25:22

    If you use -split, you have to foreach through the array. The -replace operator will do the whole array at once.

    by dragonfly26 at 2013-02-25 00:19:12

    Thanks guys for the helpful answers

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