Notify on Threshold Exceeded

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This topic contains 3 replies, has 3 voices, and was last updated by

2 years, 3 months ago.

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  • #59946

    Points: 23
    Rank: Member

    I have a script that will Notify when a threshold value is exceeded. I have most of the code of the code in place , except the threshold part does not render logically correct.
    I have placed below the part of the code giving me a problem. I am not sure why it says 7 is greater than 10.
    Please help. Thanks

    $MaxQueueCount = 10
    $FileQueueCount  = "c:\Logs\QueueCount.txt"
    $var = 7
    $var > $FileQueueCount
    $QueueCount = Get-Content -path $FileQueueCount
    write-output "QueueCount = $QueueCount"
    If ($QueueCount -ge $MaxQueueCount) 
        $Notify = 1
        write-output "$QueueCount is greater than $MaxQueueCount"
  • #59950

    Points: 1,811
    Helping HandTeam Member
    Rank: Community Hero

    What's line 4 meant to do?

  • #59952

    Points: 1,166
    Helping Hand
    Rank: Community Hero

    You're comparing a string with an integer. That always produces confusing.
    First you set $MaxQueueCount to 10 – that's an integer. Then you fill $FileQueueCount with the path to a file. Then you set $var to 7 – that's an integer either – yet. Then you write this integer to the file the path you stored before in $FileQueueCount. Now you fill in $QueueCount with the text (string) of this file. After you showed the content of the variable $QueueCount on the console you compare then the content of the variable $QueueCount, what's still a string, with the content of the variable $MaxQueueCount – what's an integer. If I'm not wrong has 7 the ASCII code 55 – so it's greater than or equal to 10. 😉

    To correct your code and produce the result you probably expect you can do either this

    $QueueCount = [INT](Get-Content -path $FileQueueCount)

    or this

    [INT]$QueueCount = Get-Content -path $FileQueueCount
  • #59970

    Points: 23
    Rank: Member

    Thanks Olaf. You are the man !!!!
    That fixed it

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