Regex replace escape $ This topic contains 2 replies, has 2 voices, and was last updated by Adam Weigert 3 years ago. Author Posts June 1, 2015 at 4:41 am #25842 Adam WeigertParticipant Trying to get -replace to escape the first $ in this statement: 'TRUE' -replace '(TRUE|FALSE)','$$1' Have tried \, and ` with no luck. It just outputs $1 each time. Thoughts? June 1, 2015 at 4:45 am #25843 Dave WyattModerator Are you trying to replace 'TRUE' with '$TRUE'? If so, you need one more $ in your string. (The first two $$ are a literal $ in the output, and then $1 is the replacement token). As a bonus, here's how you'd update your pattern to only inject the dollar sign if it wasn't already there: Edit: Moved code over to a gist, the forum was converting some of my single-quotes to double for some weird reason. June 1, 2015 at 4:59 am #25844 Adam WeigertParticipant Thanks just tried that lol. Author Posts You must be logged in to reply to this topic.