Regex replace escape $

This topic contains 2 replies, has 2 voices, and was last updated by  Adam Weigert 3 years ago.

  • Author
  • #25842

    Adam Weigert

    Trying to get -replace to escape the first $ in this statement: 'TRUE' -replace '(TRUE|FALSE)','$$1'

    Have tried \, and ` with no luck. It just outputs $1 each time.


  • #25843

    Dave Wyatt

    Are you trying to replace 'TRUE' with '$TRUE'? If so, you need one more $ in your string. (The first two $$ are a literal $ in the output, and then $1 is the replacement token).

    As a bonus, here's how you'd update your pattern to only inject the dollar sign if it wasn't already there:

    Edit: Moved code over to a gist, the forum was converting some of my single-quotes to double for some weird reason.

  • #25844

    Adam Weigert

    Thanks just tried that lol.

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