subtended distance [math]::?(?)

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1 year, 9 months ago.

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  • #72643

    Points: 0
    Rank: Member

    Having trouble working with the following math problem.
    Distance=cot (64.3/2)*(60/2)

    With the following info; 64.30 mils is the angle, 60 meters is the base, solve for distance
    On my sr56 calc it was entered like so
    64.30/2 x .05625=tan 2nd tan * 60/2=950.16 meters



  • #72679

    Points: 41
    Rank: Member

    Sorry, I don't understand the math side of it but if you want a cotangent function you derive it from the tangent function:


    I'm assuming your trig is correct 🙂 so I guess it would be something like:

    Distance = 1/[math]::tan((64.3/2))*(60/2)

    Wolfram Alpha and PowerShell give the same answer for that so hopefully that's correct – it's nowhere near 950 meters though...

    • #72703

      Points: 0
      Rank: Member

      Thanks for your help. Your suggestion works with the additional information that [math]::tan($angle) is expecting the angle to be in radians but I was giving it the angle in degrees. Adding $vAngleInDegrees / 180 * [math]::PI fixed that.
      I guess its just me but I was surprised I didn't find any powershell examples of subtended distance.
      On the off chance someone else may find it helpful.

      $vSubtendedDistance=((1/([decimal][math]::Tan(($vAngleInDegrees / 180 * [math]::PI))))*$vBase/2)

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