Why does this work?

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This topic contains 4 replies, has 4 voices, and was last updated by

9 months, 1 week ago.

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  • #111766

    Topics: 2
    Replies: 1
    Points: 1
    Rank: Member

    Why does ($a = "this") return "this"? Also, what is that return/output called?

    Is there an implicit return there? I know ("this") returns "this", but I don't understand why ($a = "this") returns "this".

  • #111778

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    Helping Hand
    Rank: Contributor



    because it invokes the default cmdlet


    in other words,


    is the same as

    write-output "this"


    $a = "this"

    is a simple variable assignment that outputs nothing. Nevermind that PowerShell also "determines" the data type of the variable $a on the fly

    However, when you enclose an expression in brackets like:

    ($a = "this")

    Here's what happens:

    – PowerShell evaluates the expression "this", next

    – PowerShell "picks" a suitable data type for variable $a, next

    – PowerShell assigns the $a variable the value from the expression "this", next

    – PowerShell also puts the value from the expression "this" in the stio pipeline (outputs it to console)

    This is useful in if statements or while loops where you want to evaluate an expression/condition as well as save it to a variable for further processing in the script block of the  if statement or while loop for example.

  • #111781

    Topics: 5
    Replies: 21
    Points: 26
    Rank: Member


    With PowerShell, toi do not have to type thé variable, like you Say it's implicite.


    If i do

    $x ="test"

    Write-host " Valeur de X : $x"

    It will equal to Valeur de X : test.

    And the variable is a string.


  • #111784

    Topics: 5
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    Sorry, i haven't saw your replay Boutros.

  • #111788

    Topics: 22
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    Helping Hand
    Rank: Community Hero

    That's a nice way to do an assignment with a "passthru", thanks. I've seen people do something like this, but it fails:

    $a = 'hi' | measure

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